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	<title>Comments on: Address Book Find Duplicates</title>
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	<description>Like a fortune cookie, only without the fortune, and not a cookie.</description>
	<pubDate>Mon, 06 Oct 2008 21:54:40 +0000</pubDate>
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		<title>By: Matt</title>
		<link>http://schinckel.net/2007/08/30/address-book-find-duplicates/#comment-2336</link>
		<dc:creator>Matt</dc:creator>
		<pubDate>Fri, 31 Aug 2007 09:39:55 +0000</pubDate>
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		<description>Hmm, a little more difficult than I'd first assumed.  Getting the phone number of a person is easy (once you grasp that you need to get value of phone of person, which is a huge departure from virtually every other AppleScript dictionary), but finding other people with the same phone number isn't so.

The problem is compounded by the fact that the way numbers is stored is related to how they are entered.  For instance, if I enter the phone number as "0487483765", it is stored as such, even though I have entries set up so it is displayed as "0487 483 765", and it won't match up with a phone number entry I have entered in that format.

You might be able to get over it by going through each person, and looking for combinations that match the number, but this would start to take a bit of time.</description>
		<content:encoded><![CDATA[<p>Hmm, a little more difficult than I&#8217;d first assumed.  Getting the phone number of a person is easy (once you grasp that you need to get value of phone of person, which is a huge departure from virtually every other AppleScript dictionary), but finding other people with the same phone number isn&#8217;t so.</p>
<p>The problem is compounded by the fact that the way numbers is stored is related to how they are entered.  For instance, if I enter the phone number as &#8220;0487483765&#8243;, it is stored as such, even though I have entries set up so it is displayed as &#8220;0487 483 765&#8243;, and it won&#8217;t match up with a phone number entry I have entered in that format.</p>
<p>You might be able to get over it by going through each person, and looking for combinations that match the number, but this would start to take a bit of time.</p>
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